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4x^2+60x-64=0
a = 4; b = 60; c = -64;
Δ = b2-4ac
Δ = 602-4·4·(-64)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-68}{2*4}=\frac{-128}{8} =-16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+68}{2*4}=\frac{8}{8} =1 $
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